creating fields in a layout

Hi, I'm wondering what is wrong with the code that I have here. I want 9 fields to appear across the screen but I don't seem to be able to get them out of the block or string that they are in and append them to the layout. Here is the code: R E B O L [] lo: [ across ] for i 1 9 1 [ -repend lo [ rejoin ["fld" i ": " "field"]] ] view layout lo

>> repend lo [ to set-word! join "fld" 1 'field ] == [fld1: field]

Hi Graham, Thanks for that. But where can I find that in the documentation?

You have to understand what the difference between words and strings is. Something like [ field1: ] is a set-word! in a block. You can start with a word! or a string! to set-word! 'field1 or to set-word! "field1"

This is pretty foundational stuff. If you haven't read a book on programming in Rebol, I suggest you do so and get this (now) free book http://www.lulu.com/shop/olivier-auverlot-and-peter-william-alfred-wood/rebol-a-programmers-guide/ebook/product-17515075.html

Thanks for the reference. Now I have expanded the program and would like it to create more rows but now my i variable does not have a value which I suppose is covered in the book. Here is the code. Perhaps you would be so kind as to tell me what the trouble is with the i variable? R E B O L [] lo: [ across space 0 ] i:0 for j 1 20 1 [ -for k 1 9 1 [ --i: i + 1 [ ---repend lo [to set-word! join "fld" i 'field 100] --] -] -repend lo 'return ] view layout lo

[ repend lo [to set-word! join "fld" i 'field 100] ] is just a block. You're not doing anything with it. I suspect you want for k 1 9 1 [ repend lo [to set-word! join "fld" ++ i 'field 100] ]

Yes that works like a million bucks. Thx R E B O L [] lo: [ across space 0 ] i: 0 for j 1 20 1 [ -for k 1 9 1 [ --i: i + 1 --repend lo [to set-word! join "fld" i 'field 100] --] -repend lo 'return ] view layout lo

Hi If Graham or Nick or anyone could answer this, I hope it will be instructive. When Graham suggested ++ i, instead of i: i + 1 he was assuming a fuction: ++: func ['word] [set word 1 + get word] Of course, that works but why? I assumed you could write a function as follows: ++ func [num] [num: num + 1] . That does NOT work over the function suggested by Graham. But why? Thx for any help.

'num is a local variable in the function. It doesn't change the value of the word outside that context.